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Intro Physics I (Phy.211) 2010 Fall

Topic Two - external Force thru time causes momentum to change ; acceleration


Readings for Topic 2 : Readings for Topic 2 :

Force : Ch.5 § 1-2
momentum change : Ch.10 § 3
acceleration : Ch.2 § 4-6
vectors : Ch.3 § 1-3
v(t) & x(t) : Ch.2 § 7


Home-Work PRACTICE QUESTIONS for Topic 2 ...( NOT for grading ...):
      (numbers refer to Ohanian Physics for Engineers,3rd ed.)

Force : ch.5 prob. 5,6,7,9,11,16,20 , 4 , 15,18
momentum change : ch.10 prob. 57,63,60 , 23 , 21(a),27,26,29
acceleration : ch.2 prob. 35,37,53,60,62,65,71,72,83 , 97 , 94,
v(t) & x(t) : ch.2 prob. 40,41,42,44,45,49,50 , 103,104
triangle trig: Ch.3 1(t?) ; probs 1,5,11,16,20,29,31,39,43,65 ; Ch.4 mult.choice 4,9,12 ; prob 16,17,19,68,28,31
Sums & Relative vectors: Ch.3 mult.choice 3,9,12 ; concepts 1,3,10 ; probs 4,9,18(components!),36,44,52 ; Ch.4 prob 18,24


Rules for Working on Homework for Grading:

Presenting someone else's work as if it was your own work
    is a violation of Marshall's Academic Dishonesty Policy.
This "work" includes the physical Work of pushing a pencil across a page, or typing on a keyboard
    and also to the artifact created by those actions -
    work includes the mental effort used in performing these activities,
    and also the thinking that was needed to create the response.

DO NOT COPY other people's homework solutions!

How to work with one or two study partners (or a tutor), and not copy :
                        (no, a group over 4 is not for learning)
  0.  draw your own diagram first ... then show ... reach a consensus diagram to answer
    (re-read & argue as needed)
  1.  now use your own thought process, to come up with an answer
    (get "unstuck" with "hints" of a few words - not "formulas")
  2.  do your own algebra, substitute your own values in, and do your own calculator entry.
  3.  then check with your study partner's answer (number and units)
  4.  have each describe their solution in words only (no math) ... (is their logic good?)
  5.  if your answers disagree , check each other's values for intermediate results


HomeWork 5 (classes 7 & 8) for grading , due Wednesday Sep.08

  1. A 50[kg] ice skater travels counter-clockwise around a 3m radius circle at constant speed ...
      ... with the circle center at origin : at t=0 she is 19.5° past the x-axis
      ... 1.335 seconds later she still has to go 19.5° to get to the y-axis . Find vector components for :
          a) initial location (t=0)   b) later location (t=1.335[s])   c) average velocity ... keep several digits .
          d) Determine the constant speed, from the fraction of the circumference traveled (51°/360°)
          e) how does this compare with magnitude of the average vavg .
  2. . . . same ice-sketer scenario . . . use the constant speed , along the circle , to determine components for
          a) initial velocity   b) velocity at t=1.335[s]  
          c) average acceleration   d) average Force [from a]   ... e) what external object applied that Force?
  3. A tower for radio antenna is 30[m] tall ; at its top, three guy wires apply Forces (3-d problem!)
        F1 = 500[N] Eastward + −700[N] Upward (pulling "downward", toward its anchor on the ground)
        F2 = 1000[N] , in the direction 40° downward from horizontally North ;
        F3 = |F3| at a 45° angle below horizontal ... toward an anchor which you need to locate.
          0) Draw a "side view" for F2 (seen from the East so that F2 is along your paper)
          ... what is F2 's North component?
          a) Draw a "top view" for all 3 Forces applied to the tower top
          ... What is the "East" component , and the "North" component for F3 , if the tower top has a = 0?
          b) Use Pythagoras to find the total "horizontal" component for F3 .
          c) Draw a "side view" for the tower, with guy wire 3 along the paper ... how far from the base of the tower should guy wire 3 be anchored?
          d) Draw a "side view" for F3 , with that Force along the page ... what is F3 's "Upward" component?
          e) What Force from the ground would make all 4 Forces "add up" to zero? (ignore weight)
  4. A 1200[kg] bison has been roped by 2 bison ranchers :
        rope one pulls the bison directly along x with 400[N] Force toward rancher 1;
        rope two pulls the bison toward rancher 2 , at 53° from −x toward +y , with Tension 800[N] .
          a) compute the net Force (vector!) applied to the bison by these two ropes
          b) compute the expected acceleration of the bison , in magnitude and direction .
      The bison is seen accelerating 2× that quickly, but at a 30° angle counterclockwise from that direction .
          c) What other Force (component, or strength & direction) is being applied to the bison?
          . . . what might be causing that Force? (speculate!)

Do something different during the Monday Holiday !


HomeWork 4 (classes 5 & 6) for grading , due Wednesday Sep.01

  1. The lab's 0.5[kg] fan car was boosted (by hand) to have −2 [m/s] at t=0 ... by t=4.5 [s], its velocity was 1 [m/s].
          a) what was its acceleration during that 4½[s] ?
          b) When did it have v=0?
          c) How far did it travel, from t=0 until it (momentarily) stopped?
          d) What Force must've been applied to the car during that 4½[s]?
  2. A grocery cart was moving 2.0[m/s] ; then has a −60[Newton] Force applied to it for 2[s] , while it travels 2.4 [m].
          a) what was the grocery cart's acceleration? {hint: Δx => avg.v => Δv}
          b) What should've been the cart's momentum change?
          c) How much mass does the cart have ?
          d) If a 30[N] Force had been used, how far would it have traveled?
  3. The 0.5[kg] lab cart's fan is 6" (=150mm) diameter; suppose it pushes air thru with speed 2.2[m/s].
          a) what Volume of air passes thru the fan every second?
          b) what's the mass of air that goes thru each second? {ρm,air ≈ 1.28 [kg/m³]}
          c) what should be the change in the cart's momentum, during each second?
          d) What would be the cart's acceleration (with this motor speed setting)
  4. Suppose a 240[kg] motorboat was going 15[m/s](î) when its engine is shut off (defining t=0) ;
      suppose that 4[s] later its speed is 10.607[m/s] , and v(t=8[s]) = 7.5[m/s].
          a) compute the average acceleration (vector!) for the first time interval, and for the second time interval.
          b) calculate the average Force during the first interval and the second interval .
          c) compute the average velocity during the first interval and during the second interval.
          d) compare each average Force to the relevant velocity   (i.e, divide F by v) ... comment.

Topic 1 Reminders :

(to topic 1 summary)

Units are more important than the number ; the "thing that it is" is more important than the units
... even more important is whether it is an instantaneous condition , or an ongoing process
... maybe most important is whether the thing describes an object , or the environment the object is in .

You should draw a sketch of each situation , label relevant quantities on the sketch , in symbols
. . . the ones you "know" values for , and the ones still "unknown" => especially the answer subject !

All of your statements should begin with a subject symbol , before the predicate "=" , then the object.
. . . the symbol "=" can be read as "is" ; but you should recognize (and try to use) more precise meanings
      including : "is defined as" , "causes" or "produces" , "comes from" or "is caused by" , "is determined by" ...
      . . . (did you notice that none of this list is reflexive? that none are symmetric? ... which ones are transitive?)

The first statement in your answer should be a general statement , in symbols , about the situation or scenario
. . . we try to use meaningful symbols for nouns - often abbreviations for a phrase
      we routinely modify nouns with adjectives and prepositions ; these are written as subscripts .
. . . the "climax statement" should begin with the desired unknown as its subject . . . (earlier ones don't need to)
. . . perform the same computations on the units that you do on the numbers

. . . you'll learn much more (with little more effort) if you de-brief yourself after getting the answer :
      a) typical values at the scale of this scenario : is the answer the "right size"? why is it so big or so small?
      b) improve your effectiveness : what did I get stuck on? what got me un-stuck? how to be stuck for less Δt ?
      c) how physical quantities relate to each other: if given#n was 2× as big, result#a would be ____ × bigger ...

- - - choose an origin for time and location - - - to make important condition properties - - - zero - - -

If you start your stopwatch at the "right" instant (defining t=0) , you can make the initial time ti = 0
      so that Δt   (= tafter - tbefore)   becomes just   t .
. . . you might want to make x0 = 0 , or v0 = 0 (or at least known) , or ...


Topic 2 Summary :

Things CHANGE
They were NOT allowed to change in the old Topic 1 scenario ... (except location)

the NEW approach , in Topic 2 , which allows them to change ,
      is to distinguish the "Object" that is being investigated : "inside the system"
      from the "Environment" that object is immersed within : "outside the system" .
Topic 1 statements are all about the object system itself (presuming no environment).
. . . it is traditional in Physics to treat the object as "passive recipient" , and the environment as the "active subject".

The mass of water in your cup can change ... if some of it leaves the cup ... or if some enters the cup.
. . . The "object system" is your cup ; there is a "system boundary" that separates "in the cup" from "outside it".
If there is less water inside than before, it means that water flowed across this boundary in an outward direction.
Δminside / Δt = −ρA·v . . . where A is the outward-pointing Area that had water flowing through it , with velocity v .


Important Statement #2 about How the Universe Works :

Force being applied to an object for a time duration CAUSES the object's momentum to change.
... the Force is applied by the subject - distinct from object - as the object's environment .
. . . While the Force is being applied , a process is occurring (Impulse) :   on objectFby subject Δt = Δp   .

Re-arranging the two changes into a ratio =>   on objectFby subject = Δp/ Δt
. . . Force depends on location ... IF   F(r) has no dis-continuity , the limit as Δt→0   will exist ... (even if F(r) is not smooth)
=>   F = dp/dt , as a derivative .

Since the object's mass is constant ,
=>   F = m· Δv / Δt =   m·a . . .
  This acceleration a has direction ... same direction is positive as for x , and v , and p .
. . . (by now you habitually indicate the "+'ve" direction on your sketch ...)
  this a is the average value that exists for the duration   Δt   of the applied Force . . .
. . . connects the earlier condition (v1) with the later condition (v2) .

Since momentum , as a function of time has to be smooth through time (with no "corners") , the limit as Δt→0 exists , and
=> a(t) = dv(t)/dt   , as a derivative .


(Reminder, definition of average velocity) Important Kinematic Equation #1 :   vavg ≡ Δr / Δt
=> place story line :   rstart + vavg·Δt  =  rend                             (acceleration is not explicit)

(definition of average acceleration) Important Kinematic Equation #2 :   aavg ≡ Δv / Δt
=> motion story line:   vstart + aavg·Δt  =  vend                           (displacement is not explicit)

IF acceleration is constant during the interval Δt :   vavg  =  vstart + ½ Δv  =  vend − ½ Δv  =  ½ ( vstart + vend ) .
=> place story w/ accel : Kinematic Equation set #3 :   has 3 different "wordings" mixing the info of #1 and #2 )
. . . (a) . . . rstart + vstart·Δt + ½ aavgt)2  =  rend       (ending velocity is not explicit)
. . . (b) . . . rstart + vend·Δt − ½ aavgt)2  =  rend         (starting velocity is not explicit)
. . . (_) . . . rstart + ½ (vend2vstart2) / a  =  rend                               (how to divide by a vector? Re-Write!)
. . . (c) . . . v2start + 2 aavg·Δr  =  v2end                             (time duration is not explicit)
      CAUTION : avoid form "c" until you understand multiplication of vectors ... the directions of   a and Δr   are important !
      caution : avoid form "c" until you find out how to identify   v²   on a diagram ... it discards direction of both velocities


- - - NOTICE - - - which quantity - - - does NOT explicitly show - - - in each equation above - - -

Solvable Kinematic scenarios can only have 2 __TWO___ of these quantities as unknown
. . . make sure the other 3 are __ON_YOUR_DIAGRAM__   . . .(4, if you have xi and xf , instead of Δx )
Your diagram should tell you whether you need to "sub-contract" to obtain a value from a preliminary scenario ...

Solve part (a) for a's unknown , by using whichever equation is _missing_ part b's unknown .
Read the equation as words ... appropriate to the scenario ...
... then , do symbolic algebra to isolate a's unknown . . . RE-READ YOUR RESULT as words
... when satisfied that the relationship is reasonable, plug numbers [ WITH UNITS ! ] and compute your result
      . . . THINK ABOUT whether it's ABOUT RIGHT , size-and-unit-wise !
... finally , you can use any of the OTHER equations to calculate b's unknown
      . . . even those which need to use a's _now_known_ .

Dynamic scenarios _imply_ a by telling F and m . . . or Δv , by telling Δp and m . . . or combinations with Δt

- - - - the KEY is - - - to TRANSLATE the STORY-LINE - - - to a SYMBOLIC STATEMENT - - -


Quantities which have direction are called vectors. Vectors are drawn as arrows (with labels, of course).
... we will pattern our treatment of all object vectors on Displacement .
We will always use coordinates with axes that are perpendicular to each other ; then,
motion in any direction is independant of motion in all other directions
. . . an event condition relates these directions by its time
. . . algebraically, the key is to keep each component (x) separate from the others (y and z) !
      then , a "big & scary" 2-dimensional scenario becomes 2 "small" 1-dimensional scenarios ... connected via time .

Vector representations : first choose an origin and coordinate system (showing each positive direction).
drawing : a location vector is drawn as an arrow with its tail at the origin, its tip at that location.
      this represents a location as if it is a radially-pointing range at some angle from the coordinate axes ... hence the abbreviation r .
. . . vectors of other quantities can have their tail at the object being described,
      but must point in the direction of the quantity (e.g, v in velocity's direction).

bold italic letters represent vector quantities !
component : The ordered set of the location coordinates ( x , y , z ) . . . = (right , forward , up)   or   (East , North , Zenith)
      is the algebraic way to write this location vector (Cartesian component form)
. . . a velocity vector is written as the set of velocity components ( vx , vy , vz ) in the same order ... .

In almost every case, it is best to :
0) diagram the "Before" scenario ... include arrows (and labels!) for the vector condition quantities.
½) notice which vector quantities might be different in the "Meanwhile" and the "After" diagram
1) draw and label the important process quantities , from Before to After ,along the path taken.
2) choose a coordinate system ; often parallel (and perp.to) the path v or p ... except in free-fall .
3) split important vector quantities into (parallel , perpendicular) or ( horizontal , vertical ) components.
4) write how the each direction's vector quantities relate to one another ... or to TIME.

Addition : drawing : usually done on a small coordinate system , separate from the main diagram (so it doesn't get cluttered).
      the first arrow tail is at the origin of the addition coordinate axes (x=0,y=0,z=0).
      its tip points the same direction from its tail as it does in your sytory-book diagram ... to ( x1 , y1 , z1 ).
. . . the vector being added to the previous has its tail placed at the previous tip
  its tip points the same direction from its tail as it does in your story-book diagram ... to (x1 + x2 , y1 + y2 , z1 + z2 ).
. . . vector arrows are appended tail-to-previous-tip in sequence, keeping each aligned with its arrow on the first diagram.
The Sum ("Result for the addition") of the vectors is the arrow from first tail (origin) to last tip .
algebraically : the Result of the addition is the list of components : (x1+x2+x3... , y1+y2+y3... , z1+z2+z3... ) .

Adding a vector to itself results in a vector twice as long , in the same direction ; i.e, v + v = 2 v ...
. . . the negative of a vector points in the opposite direction
... a vector added to its opposite ... Δx + ( − Δx ) ... makes the "zero length vector" ... = 0 = (0, 0, 0) .


Process quantities ... displacement (Δr) , boost (Δv) , Impulse (FΔt) , Action (Δx) ... add sequentially
  make sure the durations being added DO NOT OVERLAP . . . change = change   so , there is always one Δ in each term !

Condition vectors ... location , velocity , acceleration , momentum , Force ... are added at the instant of that condition
. . . it is the Sum of simultaneous Forces that cause the effected mass to accelerate (at that instant) : Σ F = m a .


(to
topic 3 summary)

Unit 1 : Newtonian (Force) ViewPoint

Readings (169 pages) and Schedule Plan

-Topic 1: location, mass, time ; velocity, momentum ; Action − (50 pgs)
      class 1: Ch.1 §1 − §6 (18 pgs)
      class 2: Ch.10 §2 (10 pgs)
      . . . >> HW 1 ("location") due Wed Aug.25
      class 3 : Ch.2 §1 − §3 (10 pgs) + Ch.4 § 6 (3 pgs)
      . . . >> HW 2 ("velocity") due Fri Aug.27
      class 4 : Ch.5 §1 (2 pgs) + Ch.10 § 1 (7 pgs)
      . . . >> HW 3 ("momentum") due Mon Aug.30

-Topic 2: Force causes momentum to change with time (57 pgs)
      class 5: Ch.2 §4 − §5 (10 pgs)
      class 6: Ch.5 §2 (5 pgs)
      . . . >> HW 4 ("F=ma") due Wed Sep.01
      class 7: Quiz 1 . . . then Ch.3 §1 − §3 (11 pgs) Ch.4 §1 − §3 (10 pgs) + Ch.2 §7 (3 pgs)
      . . . >> HW 5 ("F=ma") due Fri Sep.03
      class 8: Ch.2 §6 (5 pgs) + Ch.4 §4 − §5 (8 pgs)
      . . . >> HW 6 ("Fgrav = m g") due Wed Sep.08

-Topic 3: more kinds of Force
      No Monday classes     : (
      No Monday classes . . .
      class 9: Quiz 2 . . . then Ch.5 §3 − §4 (12 pgs)
      . . . >> HW 7 ("ΣF=ma") due Fri Sep.10
      class10: Ch.5 §5 (7 pgs) + Ch.11 §1 , §3 (8 pgs)
      . . . >> HW 8 ("Force Functions") due Mon Sep.13

      class11: Ch.18 §3 − §5 (9 pgs) + Ch.6 §2 (2 pgs) + Ch.14 §4 (5 pgs)
      class12: Ch.6 §1 (8 pgs) + §3 (7 pgs)
      . . . >> HW 9 ("Pressure & Elasticity") due Wed Sep.15
-Topic 4: deeper causes for Forces
      class13: Quiz 3 . . . then Ch.6 §4 (1 pg) + Ch.9 §1 − §3 (10 pgs)
      . . . >> HW10 ("Gravitation") due Fri Sep.17
      class14: Ch.10 §3 (4 pgs) , Ch.11 §4 (8 pgs)
      . . . >> HW11 ("momentum exchange") due Mon Sep.20

      class15: Force Sum practice
      class16: More Force Vector Sum Practice
      . . . >> HW12 ("F perp. v") due Wed.Sep.22
      class17: Quiz 4 . . . then Review Unit 1?
      . . . >> no HW , but practice Exam on-line
      class18: introduce Unit 2? ... Ch.7 §1 − §3 (13 pgs)

      class19: Exam 1 - plan for 75 minutes long . . .
      class20: Ch.7 §4 (6pgs) + Ch.8 §1 − §2 (12 pgs)




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