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Intro Physics I (Phy.211) 2010 Fall

Unit 2 ; Topic Six - Other Energies , and E transformations


Plan for Unit 2 :
-Topic 5:
      Work by Force & Kinetic Enery : Ch.7 § 1,2,3
      . . . (3-pt HW due Mon.Oct.04)
      Potential Energy functions : Ch.7 § 4 ; Ch.8 § 1,2
      . . . (3-pt HW due Mon.Oct.04)
    Quiz Wed.Oct.08

-Topic 6:
      Transformed Energy : Ch.8 § 3,5 ; Ch.9 § 5 ; Ch.18 § 6
      . . . (HW due Mon.Oct.11)
      Energy transfer : Ch.10 § 4 ; Ch.11 § 1,2,3,4 ; Ch.9 § 4
      . . . (HW due Wed.Oct.13)
    Quiz Wed.Oct.13

-Topic 7:
      Rotational Energy : Ch.12 ; Ch.13
      . . . (HW do by Fri.Oct.15)
  - plan for Exam 2 Mon.Oct.18


Home-Work PRACTICE QUESTIONS for Topic 6 ...( NOT for grading ...):
      (numbers refer to Ohanian Physics for Engineers,3rd ed.)

Combustion Energy : ch.8 prob. 35,36,37,39(80%→heat),41,42,43 ; 44,45,47,48,49,51,53,101
Power in Transformations : ch.8 prob. 54,55,56,57,59,62,64,65 ; 67,69,71,72,76,77,78,85,87,89,96
Gravitational PE : ch.9 prob. 45,47,51,53,55 , 57,61,62,66 , 70,74
Energy in Orbits : ch.9 prob. 38,39 , 42,43,40,42,43 , 69,67,72,73,86
Energy in Collisions : ch.10 prob. 52,53,54 ; 57,68,69,71,75,72 ; 73 ;
            Ch.11 prob. 1,5,9 ; 16,18,19,23,26,27,29,30,31,32 , 37,41,42 , 45,47,53,55,57,61,63,65,66


Homework 10 (from Mon.Oct.04 - Fri.Oct.08 ... classes 23 - 26) - due Tue.Oct.12
  1. (Ch.8 prob.39, 43, & 55 combined) 30 years ago Bryan Allen supplied (average) 330 [Watt] ,
       by turning bike pedals about 6 radian each second, at radius 0.25 [m] from the crank shaft ,
       flying across the English Channel in 2 [hr] + 49 [min] ; he expended 5× that Power during the exercise.
          a) compute the Energy , in [Joules], that Bryan Allen transfered to the airplane during the flight.
          . . . Explain why the ending speed was NOT   v = √(2E/m) ...
          b) what Force (average) would be required to do that amount of Work?
          c) How much "food Energy" was "burned" by Allen during this ordeal?
          . . . what do you think happenned to the Energy that did not get transferred via Work on the pedals?
          d) convert the Energy consumed to [kcal]; how many 290 [Cal] 20[oz] bottles would this require?
  2. ("real" Ch.8 prob.43) A 100[kg] human will "burn" (≈ "transform from chemical E") 140 [kcal/hr] standing
          ... 320 [kcal/hr] walking 5[km/hr] ; 800 [kcal/hr] jogging 8[km/hr] ; 1820 [kcal/hr] running 16[km/hr]
          a) calculate the Energy he will transform , while walking 2.5[km] .
          b) calculate the Energy he'll transform : while jogging 2.5[km] , then stand for the remainder of ½ hour .
          c) calculate the Energy to run 2.5[km] (not Ohanian's "1520") , then stand for the rest of the ½ hour
        . . . burning gasoline releases about 130 [MJ] per gallon . . . convert to [kcal] . . .
          d) How much Energy would a 25 [mile/gallon] car burn, while traveling 2.5[km] (suppose 50 [km/hr])
  3. . . . same 100 [kg] human traveling 2.5[km] scenario . . . Topic 1 defined "Action done" as ΔS = Δr .
          a) calculate a formula for Action done, as a function of KE (instead of momentum).
          b) compute the Action the 100[kg] person does , in the 3 modes of travel
          c) compute the locomotion efficiency , in [km/kcal] at these 3 speeds (don't include "standing Energy")
          d) for the person, does efficiency seem to vary with the Action ? Does the 1000[kg] car fit this trend?
  4. (like Ch.9 prob.38) Comet Halley's speed was 54.5 [km/s] when closest to the Sun (0.585 a.u.) recently .
          a) calculate the angular momentum that 1 [kg] of Comet Halley ice had , at perihelion ("around the Sun").
        . . . this is constant , unlike v . . . can you write a KE formula using L instead of v ?
          b) use L to calculate the KE that 1 [kg] of Comet Halley had at perihelion (in 1986).
        Comet Halley's aphelion ("high from Sun") was 35.2 [a.u.] . . . (in 1948)
          c) use the L for 1[kg] to calculate the KE that 1[kg] of ice used to have, at aphelion.
          d) compute KE+PE at aphelion (for 1[kg]) ... then compute KE+PE at perihelion ... comment?

Topic 1 Reminders :

(to topic 1 summary)

USE UNITS all thru your answer ... don't just append them onto the final number !

Put symbols on a sketch, as you read . . . use meaningful phrases : "v_match" , "catch" , "ground" "turn-around"
. . . show process spans as brackets or vector arrows , with words like   "average" , "losing" , "gaining" , "t=0→2" ...

Write statements as symbols first ... each statement has a SUBJECT ... manipulate symbols before plugging numbers.
. . . keep track of adjectives such as   "initial" , "average" , "final" , "stopped" . . . "change"

Topic 2 Reminders :

(to topic 2 summary)

subscripts for "total" or "system" , "part A" ...

keep track of the SOURCE for the external Forces applied to the (passive) object

Recognize whether you are predicting based on theory . . . reasoning from causes to their effects ... (what should it do?)
      or whether you are deducing from observation . . . (what does this imply about it?)

Get un-stuck (often) by wondering "why isn't it the same as it used to be?"

Topic 3 Reminders :

it's the Sum of external Forces that cause an object's mass to accelerate subscripts for "total" or "system" , "part A" ...

once you separate vectors into components, keep each component separate from the others!
ΣF = ma , for each component separately.

Topic 4 Reminders :

Name each Force by the source of that Force ... its cause ... a function of the environment.

spring Force : Fspring = − k s ... opposite the stretch vector .

Pressure Force : Fspring = P A   generally ... in a fluid , δP = ρ g δh .

Gravity : every mass in the universe contributes to the gravity field   g   at any place of interest.
... add "nearby" contributions as vectors ... gby M = G M / r²M-to-point (toward M) . . . then use   Fgravity, on m = mg ;       NOTICE : m ≠ M !


Topic 5 Reminders :

Energy is conserved quantity : Σ Ebefore   +   Σ Wby F's not in PE list   =   Σ Eafter .
  KE = ½ m v² = ½ p·v = ½ p²/m   , in any of these equivalent forms .

Each Force either does Work during motion , or has an associated PE function ... not both .
=> Wby F = Δs .
=> − dU / dr = Fr , the component along that direction (r)

  PEgravity,local = m g h , with h measured upward (z-direction) from a "zero-height reference" point
  PEelastic = ½ k s²   . . . stretch s must be measured from its relaxed length
  PEPressure = P·V   ; it is okay to measure from a non-zero reference pressure , but be consistent !
  PEGravitation = − m GM / r .
  There IS NO PE for Friction Force ... must be explicitly included as a "Work by Forces not in the PE list"


Topic 6 Summary :

the Gravitational Potential Energy of a planet , near the Sun , is negative .
As the planet-forming material fell inward from far away (where PE≈0) , to lower PE , it gained KE
. . . as the material lost some KE during collisions , it became trapped , unable to achieve the large distances that it once was at .
the amount of Energy an object needs , in order to achieve "infinite" distance , is called its Escape Energy
. . . the speed that corresponds to that much Kinetic Energy , which is the same for any mass , is the Escape Speed.

Because all source Masses contribute to the Gravitational Field g , at any location ,
      the Gravitational PE of some field mass is NOT due to any single source Mass .
. . . instead, each source Mass   Mi   contributes to the total Gravitational Potential , called VGrav , at the place of interest .
      notice that a "mass m" object at the place of interest has PE = m VGrav   when it is there ,
      but the place itself has Gravitational Potential (due to "space warp") , even if no mass is there .
=> VGrav(x,y,z) = Σ Vi . . . . . each contribution Vi = GMi /ri   , depends on distance ri from its Mass to the place (x,y,z) .


In the early 1600's Kepler analyzed data for the direction to planets as seen from Earth (mostly Tycho Brahe's data)
=> Kepler #1 : each planet path is an ellipse , with the Sun at one focus of the ellipse
. . . each planet's ellipse is stretched along its own vector , and is tilted a few degrees relative to Earth's.

=> Kepler #2 : planets move faster where closer to the Sun ... move slower where farther from the Sun
. . . r × v | is constant for each planet ;   v |   is the velocity component perpendicular to r .
. . . since each planet's mass is constant, this implies that L = r × p = r p sin(φ)   is constant (conserved).
      the angular momentum vector L only includes the angular (or tangential) velocity component ... (not radial)
. . . since the velocity's tangential component is   vφ = r ω = r (dφ/dt) ,   L = m r ² ω .
      angular momentum is equal to rotational inertia (mr ²) times the angular velocity (ω) .

=> Kepler #3 : planets with smaller orbits move (on average) faster than planets with larger orbits ... T ² ~ R ³
    . . . this works if T is in [years] , and R is in [a.u.]
      here, the average distance from the Sun   R , is half of the ellipse major axis
    . . . R = ½ ( perihelion distance + aphelion distance ) .
      if the orbit is around a planet , rather than the Sun , T ² = Morbited R ³ , with M in solar masses .
. . . we can interpret this as : (average) KEangular = ½ (4 π²) M / R ... and recognize G in these astronomical units .


An object can have non-zero KE even if its center-of-mass has zero velocity, if it is spinning.
. . . each little piece of mass is moving at different speed   v = r ω , depending on its distance from the spin axis.
=> KErotation   = ½ I ω ² = ½ ∑ m (r ω)² = L ² /(2 m r ²)

I   is called the rotational Inertia , or the (second) moment of Inertia , for the object ... depends on shape!
I = ∑ m r ²   , where r is the distance from the rotation axis to each point mass
. . . for real objects that are not made of point masses , there are two options :
    a) integrate : I = ∫ ρ r ² dV   over the entire volume of the object   (write the Volume element   dV carefully!)
    b) add pieces : Itotal = ∑ (Ipart + mpart rpart² )   (using the parallel-axis theorem ).
      ... treat object as being made from a few parts , model each part as having regular geometric shape
          ... look up a rotational Inertia formula for each "part" (in a table) around its center-of-mass
            ... pay attention to the axis location (center, or edge) for that formula!

This means that Work can be done on an object , even if the object's center-of-mass doesn't move .
      (Work is done by the Force application point moving parallel the Force)
. . . for a spinning object, the tangential Force component is the one which can do Work ; distance traveled is Δs = r Δθ .
=> WRotation = r × F Δθ = r F sin(φ) Δθ .


(to topic 7 summary)



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